## Bates/sls

Large least-squares problem (GPA) Doug Bates, Univ of Wisconsin-Madison

Name | sls |
---|---|

Group | Bates |

Matrix ID | 2218 |

Num Rows | 1,748,122 |

Num Cols | 62,729 |

Nonzeros | 6,804,304 |

Pattern Entries | 6,804,304 |

Kind | Least Squares Problem |

Symmetric | No |

Date | 2008 |

Author | D. Bates |

Editor | T. Davis |

Download | MATLAB Rutherford Boeing Matrix Market |
---|---|

Notes |
Large least-squares problem from Doug Bates, Univ of Wisconsin-Madison http://www.stat.wisc.edu/~bates The data are 10 years of grade point scores at a large state university (not mine). The covariates that are recorded with the scores are the student id, the instructor id and the department. Number of obs: 1685394, groups: id, 54711; instr, 7915; dept, 102 Even though these scores are from different semesters and one of the questions of interest is whether grade inflation has taken place, initially I fit a simple model that has an effect for the student, an effect for the instructor and an effect for the department. There is also an overall average gradepoint. The overall average is what we call a fixed effect. In computations terms this means it is estimated without a penalty. The other effects are what we call random effects. In terms of parameters we estimate a variance for each group of random effects (student, instructor and department). We assume that the random effects come from a normal (or Gaussian) distribution, which has the effect of shrinking the estimates of the individual effects towards the origin. If the variance of that distribution is large, there is little penalty and the estimates for each of the students or each of the instructors or each of the departments is close to the least squares estimate. If the variance is small then they are much closer to zero. Overall we will estimate 3 variances, 1 fixed-effect and 62728 = 54711 + 7915 + 102 random effects. The matrix we will decompose will be 62729 columns (the last column comes from the fixed-effect) and 1685394 + 62728 rows. The 62728 rows come from the penalty part and consist of an identity matrix of size 62728 with a column of zeros appended on the right. The rows determined by the data (I think of these as being the top part of the matrix but it doesn't matter if they are on the top or the bottom) consist of 54711 columns of indicators for the student followed by 7915 columns of indicators for the instructor followed by 102 columns of indicators for the department followed by a column of 1's. In general we will have columns for random effects followed by columns for fixed effects. Here the fixed-effects column is trivial but in general we may have more than 1 and they don't have to be as trivial as this. At least as far as I have been able to analyze the computation, I can allow for permutations of the columns for the random effects but I don't want to mix up the columns for the random effects and the columns for the fixed effects. I always want to keep the columns for the fixed effects as a block on the right. (Usually these columns are dense or close to it so it isn't a problem to force them to be on the right.) The reason is that I need the logarithm of the square of the determinant of the triangular factor from the random effects columns only. During the optimization phase we fix values of the three variances, update the numeric values in the matrix, decompose, calculate the determinant of the leading part of the triangular factor, and evaluate the penalized residual sum of squares. The logarithm of the determinant and the penalized residual sum of squares are combined to create a criterion called the profiled log-likelihood which is to be maximized The update operation changes the numerical values of the data-determined part according to three multipliers. The first multiplier is applied to the first 54711 columns, the next multiplier is applied to the next 7915 columns and the last multiplier is applied to the next 102 columns. The last column stays fixed. We start from the factors for the student, instructor and department then generate the indicators to form Z. The factors can be represented as integers and the response is a grade point score (allowed to be half integers). |